3x^2-27-528=0

Solution for 3x^2-27-528=0 equation:

3x^2-27-528=0

We add all the numbers together, and all the variables

3x^2-555=0

a = 3; b = 0; c = -555;
Δ = b2-4ac
Δ = 02-4·3·(-555)
Δ = 6660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6660}=\sqrt{36*185}=\sqrt{36}*\sqrt{185}=6\sqrt{185}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{185}}{2*3}=\frac{0-6\sqrt{185}}{6}
=-\frac{6\sqrt{185}}{6}
=-\sqrt{185}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{185}}{2*3}=\frac{0+6\sqrt{185}}{6}
=\frac{6\sqrt{185}}{6}
=\sqrt{185}
$